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test/buildroot: test timeout at the run level

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Check the timeout functionality at the `Buildroot.run` level not at
the `read_with_timeout` level, which is an implementation detail.
This commit is contained in:
Christian Kellner 2021-12-06 16:02:35 +00:00 • committed by mergify[bot]
parent 73dd612cad
commit 3958a6140c
1 changed files with 5 additions and 15 deletions
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20
test/mod/test_buildroot.py
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@ -4,10 +4,7 @@
import pathlib
import os
import select
import subprocess
import sys
import time
from tempfile import TemporaryDirectory
@ -176,21 +173,14 @@ def test_timeout(tempdir):
var = pathlib.Path(tempdir, "var")
var.mkdir()
monitor = NullMonitor(sys.stderr.fileno())
with BuildRoot("/", runner, libdir, var) as root:
READ_ONLY = select.POLLIN | select.POLLPRI | select.POLLHUP | select.POLLERR
poller = select.poll()
root.run(["/bin/sleep", "1"], monitor, timeout=2)
proc = subprocess.Popen(['python3', libdir + '/stages/org.osbuild.test.timeout'], stdout = subprocess.PIPE)
start = time.monotonic()
timeout = 4
poller.register(proc.stdout.fileno(), READ_ONLY)
with pytest.raises(TimeoutError):
root.read_with_timeout(proc, poller, start, timeout)
root.run(["/bin/sleep", "1"], monitor, timeout=0.1)
proc = subprocess.Popen(['python3', libdir + '/stages/org.osbuild.test.timeout'], stdout = subprocess.PIPE)
start = time.monotonic()
timeout = 0
poller.register(proc.stdout.fileno(), READ_ONLY)
with pytest.raises(TimeoutError):
root.read_with_timeout(proc, poller, start, timeout)
root.run(["/bin/sleep", "1"], monitor, timeout=0.1)