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Wizard: conflicting packages

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Disable a package if it's a conflicting module stream or if it's a non-modular package whose base name is already covered by an enabled module stream.
Disable a module if anouther package with the same name was selected.
Fixes #3274
This commit is contained in:
Katarina Sieklova 2025-06-03 14:04:14 +02:00 • committed by Klara Simickova
parent 3e4ee6891d
commit 981b62d7b0
1 changed files with 26 additions and 6 deletions
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32
src/Components/CreateImageWizard/steps/Packages/Packages.tsx
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@ -1051,7 +1051,11 @@ const Packages = () => {
let isSelected = false;
if (!pkg.type || pkg.type === 'package') {
isSelected = packages.some((p) => p.name === pkg.name);
const isModuleWithSameName = modules.some(
(module) => module.name === pkg.name
);
isSelected =
packages.some((p) => p.name === pkg.name) && !isModuleWithSameName;
}
if (pkg.type === 'module') {
@ -1059,7 +1063,9 @@ const Packages = () => {
// and its module stream matches one in enabled_modules
isSelected =
packages.some((p) => p.name === pkg.name) &&
modules.some((p) => p.stream === pkg.stream);
modules.some(
(m) => m.name === pkg.module_name && m.stream === pkg.stream
);
}
return isSelected;
@ -1077,11 +1083,25 @@ const Packages = () => {
* @returns Package (or group) is / is not selected
*/
const isSelectDisabled = (pkg: IBPackageWithRepositoryInfo) => {
const isModuleDisabledByPackage =
pkg.type === 'module' &&
packages.some(
(p) => (!p.type || p.type === 'package') && p.name === pkg.module_name
);
const isPackageDisabledByModule =
(!pkg.type || pkg.type === 'package') &&
modules.some((module) => module.name === pkg.name);
const isModuleStreamConflict =
pkg.type === 'module' &&
modules.some((module) => module.name === pkg.module_name) &&
!modules.some((m) => m.stream === pkg.stream);
return (
(pkg.type === 'module' &&
modules.some((module) => module.name === pkg.module_name) &&
!modules.some((p) => p.stream === pkg.stream)) ||
false
isModuleDisabledByPackage ||
isPackageDisabledByModule ||
isModuleStreamConflict
);
};